Optimal. Leaf size=532 \[ -\frac {\left (A b^2-a (b B-a C)\right ) (c+d \tan (e+f x))^{3/2}}{2 b f \left (a^2+b^2\right ) (a+b \tan (e+f x))^2}-\frac {\sqrt {c+d \tan (e+f x)} \left (3 a^4 C d+a^3 b B d-a^2 b^2 (5 A d+4 B c-11 C d)+a b^3 (8 A c-7 B d-8 c C)+b^4 (3 A d+4 B c)\right )}{4 b^2 f \left (a^2+b^2\right )^2 (a+b \tan (e+f x))}-\frac {\left (3 a^6 C d^2+a^5 b B d^2+a^4 b^2 d (3 d (A+2 C)+4 B c)-2 a^3 b^3 \left (12 c d (A-C)+B \left (4 c^2-9 d^2\right )\right )+a^2 b^4 \left (24 A c^2-26 A d^2-48 B c d-24 c^2 C+35 C d^2\right )+a b^5 \left (40 c d (A-C)+3 B \left (8 c^2-5 d^2\right )\right )-b^6 \left (8 A c^2-3 A d^2-12 B c d-8 c^2 C\right )\right ) \tanh ^{-1}\left (\frac {\sqrt {b} \sqrt {c+d \tan (e+f x)}}{\sqrt {b c-a d}}\right )}{4 b^{5/2} f \left (a^2+b^2\right )^3 \sqrt {b c-a d}}-\frac {(c-i d)^{3/2} (A-i B-C) \tanh ^{-1}\left (\frac {\sqrt {c+d \tan (e+f x)}}{\sqrt {c-i d}}\right )}{f (b+i a)^3}+\frac {(c+i d)^{3/2} (A+i B-C) \tanh ^{-1}\left (\frac {\sqrt {c+d \tan (e+f x)}}{\sqrt {c+i d}}\right )}{f (-b+i a)^3} \]
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Rubi [A] time = 4.09, antiderivative size = 532, normalized size of antiderivative = 1.00, number of steps used = 13, number of rules used = 7, integrand size = 47, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.149, Rules used = {3645, 3653, 3539, 3537, 63, 208, 3634} \[ -\frac {\left (-2 a^3 b^3 \left (12 c d (A-C)+B \left (4 c^2-9 d^2\right )\right )+a^2 b^4 \left (24 A c^2-26 A d^2-48 B c d-24 c^2 C+35 C d^2\right )+a^4 b^2 d (3 d (A+2 C)+4 B c)+a^5 b B d^2+3 a^6 C d^2+a b^5 \left (40 c d (A-C)+3 B \left (8 c^2-5 d^2\right )\right )-b^6 \left (8 A c^2-3 A d^2-12 B c d-8 c^2 C\right )\right ) \tanh ^{-1}\left (\frac {\sqrt {b} \sqrt {c+d \tan (e+f x)}}{\sqrt {b c-a d}}\right )}{4 b^{5/2} f \left (a^2+b^2\right )^3 \sqrt {b c-a d}}-\frac {\left (A b^2-a (b B-a C)\right ) (c+d \tan (e+f x))^{3/2}}{2 b f \left (a^2+b^2\right ) (a+b \tan (e+f x))^2}-\frac {\sqrt {c+d \tan (e+f x)} \left (-a^2 b^2 (5 A d+4 B c-11 C d)+a^3 b B d+3 a^4 C d+a b^3 (8 A c-7 B d-8 c C)+b^4 (3 A d+4 B c)\right )}{4 b^2 f \left (a^2+b^2\right )^2 (a+b \tan (e+f x))}-\frac {(c-i d)^{3/2} (A-i B-C) \tanh ^{-1}\left (\frac {\sqrt {c+d \tan (e+f x)}}{\sqrt {c-i d}}\right )}{f (b+i a)^3}+\frac {(c+i d)^{3/2} (A+i B-C) \tanh ^{-1}\left (\frac {\sqrt {c+d \tan (e+f x)}}{\sqrt {c+i d}}\right )}{f (-b+i a)^3} \]
Antiderivative was successfully verified.
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Rule 63
Rule 208
Rule 3537
Rule 3539
Rule 3634
Rule 3645
Rule 3653
Rubi steps
\begin {align*} \int \frac {(c+d \tan (e+f x))^{3/2} \left (A+B \tan (e+f x)+C \tan ^2(e+f x)\right )}{(a+b \tan (e+f x))^3} \, dx &=-\frac {\left (A b^2-a (b B-a C)\right ) (c+d \tan (e+f x))^{3/2}}{2 b \left (a^2+b^2\right ) f (a+b \tan (e+f x))^2}+\frac {\int \frac {\sqrt {c+d \tan (e+f x)} \left (\frac {1}{2} \left (2 (b B-a C) \left (2 b c-\frac {3 a d}{2}\right )+2 A b \left (2 a c+\frac {3 b d}{2}\right )\right )-2 b ((A-C) (b c-a d)-B (a c+b d)) \tan (e+f x)-\frac {1}{2} \left (A b^2-a b B-3 a^2 C-4 b^2 C\right ) d \tan ^2(e+f x)\right )}{(a+b \tan (e+f x))^2} \, dx}{2 b \left (a^2+b^2\right )}\\ &=-\frac {\left (a^3 b B d+3 a^4 C d+b^4 (4 B c+3 A d)+a b^3 (8 A c-8 c C-7 B d)-a^2 b^2 (4 B c+5 A d-11 C d)\right ) \sqrt {c+d \tan (e+f x)}}{4 b^2 \left (a^2+b^2\right )^2 f (a+b \tan (e+f x))}-\frac {\left (A b^2-a (b B-a C)\right ) (c+d \tan (e+f x))^{3/2}}{2 b \left (a^2+b^2\right ) f (a+b \tan (e+f x))^2}+\frac {\int \frac {\frac {1}{4} \left (b (2 a c+b d) \left (3 a^2 C d+b^2 (4 B c+3 A d)+a b (4 A c-4 c C-3 B d)\right )-(2 b c-a d) \left (a^2 b B d+3 a^3 C d+A b^2 (4 b c-5 a d)-4 b^3 (c C+B d)-4 a b^2 (B c-2 C d)\right )\right )+2 b^2 \left (2 a b \left (c^2 C+2 B c d-C d^2-A \left (c^2-d^2\right )\right )+a^2 \left (2 c (A-C) d+B \left (c^2-d^2\right )\right )-b^2 \left (2 c (A-C) d+B \left (c^2-d^2\right )\right )\right ) \tan (e+f x)+\frac {1}{4} d \left (a^3 b B d+3 a^4 C d-a b^3 (8 A c-8 c C-9 B d)-b^4 (4 B c+5 A d-8 C d)+a^2 b^2 (4 B c+3 (A+C) d)\right ) \tan ^2(e+f x)}{(a+b \tan (e+f x)) \sqrt {c+d \tan (e+f x)}} \, dx}{2 b^2 \left (a^2+b^2\right )^2}\\ &=-\frac {\left (a^3 b B d+3 a^4 C d+b^4 (4 B c+3 A d)+a b^3 (8 A c-8 c C-7 B d)-a^2 b^2 (4 B c+5 A d-11 C d)\right ) \sqrt {c+d \tan (e+f x)}}{4 b^2 \left (a^2+b^2\right )^2 f (a+b \tan (e+f x))}-\frac {\left (A b^2-a (b B-a C)\right ) (c+d \tan (e+f x))^{3/2}}{2 b \left (a^2+b^2\right ) f (a+b \tan (e+f x))^2}+\frac {\int \frac {-2 b^2 \left (a^3 \left (c^2 C+2 B c d-C d^2-A \left (c^2-d^2\right )\right )-3 a b^2 \left (c^2 C+2 B c d-C d^2-A \left (c^2-d^2\right )\right )-3 a^2 b \left (2 c (A-C) d+B \left (c^2-d^2\right )\right )+b^3 \left (2 c (A-C) d+B \left (c^2-d^2\right )\right )\right )+2 b^2 \left (3 a^2 b \left (c^2 C+2 B c d-C d^2-A \left (c^2-d^2\right )\right )-b^3 \left (c^2 C+2 B c d-C d^2-A \left (c^2-d^2\right )\right )+a^3 \left (2 c (A-C) d+B \left (c^2-d^2\right )\right )-3 a b^2 \left (2 c (A-C) d+B \left (c^2-d^2\right )\right )\right ) \tan (e+f x)}{\sqrt {c+d \tan (e+f x)}} \, dx}{2 b^2 \left (a^2+b^2\right )^3}+\frac {\left (a^5 b B d^2+3 a^6 C d^2+a^4 b^2 d (4 B c+3 (A+2 C) d)-b^6 \left (8 A c^2-8 c^2 C-12 B c d-3 A d^2\right )+a^2 b^4 \left (24 A c^2-24 c^2 C-48 B c d-26 A d^2+35 C d^2\right )-2 a^3 b^3 \left (12 c (A-C) d+B \left (4 c^2-9 d^2\right )\right )+a b^5 \left (40 c (A-C) d+3 B \left (8 c^2-5 d^2\right )\right )\right ) \int \frac {1+\tan ^2(e+f x)}{(a+b \tan (e+f x)) \sqrt {c+d \tan (e+f x)}} \, dx}{8 b^2 \left (a^2+b^2\right )^3}\\ &=-\frac {\left (a^3 b B d+3 a^4 C d+b^4 (4 B c+3 A d)+a b^3 (8 A c-8 c C-7 B d)-a^2 b^2 (4 B c+5 A d-11 C d)\right ) \sqrt {c+d \tan (e+f x)}}{4 b^2 \left (a^2+b^2\right )^2 f (a+b \tan (e+f x))}-\frac {\left (A b^2-a (b B-a C)\right ) (c+d \tan (e+f x))^{3/2}}{2 b \left (a^2+b^2\right ) f (a+b \tan (e+f x))^2}+\frac {\left ((A-i B-C) (c-i d)^2\right ) \int \frac {1+i \tan (e+f x)}{\sqrt {c+d \tan (e+f x)}} \, dx}{2 (a-i b)^3}+\frac {\left ((A+i B-C) (c+i d)^2\right ) \int \frac {1-i \tan (e+f x)}{\sqrt {c+d \tan (e+f x)}} \, dx}{2 (a+i b)^3}+\frac {\left (a^5 b B d^2+3 a^6 C d^2+a^4 b^2 d (4 B c+3 (A+2 C) d)-b^6 \left (8 A c^2-8 c^2 C-12 B c d-3 A d^2\right )+a^2 b^4 \left (24 A c^2-24 c^2 C-48 B c d-26 A d^2+35 C d^2\right )-2 a^3 b^3 \left (12 c (A-C) d+B \left (4 c^2-9 d^2\right )\right )+a b^5 \left (40 c (A-C) d+3 B \left (8 c^2-5 d^2\right )\right )\right ) \operatorname {Subst}\left (\int \frac {1}{(a+b x) \sqrt {c+d x}} \, dx,x,\tan (e+f x)\right )}{8 b^2 \left (a^2+b^2\right )^3 f}\\ &=-\frac {\left (a^3 b B d+3 a^4 C d+b^4 (4 B c+3 A d)+a b^3 (8 A c-8 c C-7 B d)-a^2 b^2 (4 B c+5 A d-11 C d)\right ) \sqrt {c+d \tan (e+f x)}}{4 b^2 \left (a^2+b^2\right )^2 f (a+b \tan (e+f x))}-\frac {\left (A b^2-a (b B-a C)\right ) (c+d \tan (e+f x))^{3/2}}{2 b \left (a^2+b^2\right ) f (a+b \tan (e+f x))^2}+\frac {\left ((A-i B-C) (c-i d)^2\right ) \operatorname {Subst}\left (\int \frac {1}{(-1+x) \sqrt {c-i d x}} \, dx,x,i \tan (e+f x)\right )}{2 (i a+b)^3 f}-\frac {\left ((A+i B-C) (c+i d)^2\right ) \operatorname {Subst}\left (\int \frac {1}{(-1+x) \sqrt {c+i d x}} \, dx,x,-i \tan (e+f x)\right )}{2 (i a-b)^3 f}+\frac {\left (a^5 b B d^2+3 a^6 C d^2+a^4 b^2 d (4 B c+3 (A+2 C) d)-b^6 \left (8 A c^2-8 c^2 C-12 B c d-3 A d^2\right )+a^2 b^4 \left (24 A c^2-24 c^2 C-48 B c d-26 A d^2+35 C d^2\right )-2 a^3 b^3 \left (12 c (A-C) d+B \left (4 c^2-9 d^2\right )\right )+a b^5 \left (40 c (A-C) d+3 B \left (8 c^2-5 d^2\right )\right )\right ) \operatorname {Subst}\left (\int \frac {1}{a-\frac {b c}{d}+\frac {b x^2}{d}} \, dx,x,\sqrt {c+d \tan (e+f x)}\right )}{4 b^2 \left (a^2+b^2\right )^3 d f}\\ &=-\frac {\left (a^5 b B d^2+3 a^6 C d^2+a^4 b^2 d (4 B c+3 (A+2 C) d)-b^6 \left (8 A c^2-8 c^2 C-12 B c d-3 A d^2\right )+a^2 b^4 \left (24 A c^2-24 c^2 C-48 B c d-26 A d^2+35 C d^2\right )-2 a^3 b^3 \left (12 c (A-C) d+B \left (4 c^2-9 d^2\right )\right )+a b^5 \left (40 c (A-C) d+3 B \left (8 c^2-5 d^2\right )\right )\right ) \tanh ^{-1}\left (\frac {\sqrt {b} \sqrt {c+d \tan (e+f x)}}{\sqrt {b c-a d}}\right )}{4 b^{5/2} \left (a^2+b^2\right )^3 \sqrt {b c-a d} f}-\frac {\left (a^3 b B d+3 a^4 C d+b^4 (4 B c+3 A d)+a b^3 (8 A c-8 c C-7 B d)-a^2 b^2 (4 B c+5 A d-11 C d)\right ) \sqrt {c+d \tan (e+f x)}}{4 b^2 \left (a^2+b^2\right )^2 f (a+b \tan (e+f x))}-\frac {\left (A b^2-a (b B-a C)\right ) (c+d \tan (e+f x))^{3/2}}{2 b \left (a^2+b^2\right ) f (a+b \tan (e+f x))^2}-\frac {\left ((A-i B-C) (c-i d)^2\right ) \operatorname {Subst}\left (\int \frac {1}{-1-\frac {i c}{d}+\frac {i x^2}{d}} \, dx,x,\sqrt {c+d \tan (e+f x)}\right )}{(a-i b)^3 d f}-\frac {\left ((A+i B-C) (c+i d)^2\right ) \operatorname {Subst}\left (\int \frac {1}{-1+\frac {i c}{d}-\frac {i x^2}{d}} \, dx,x,\sqrt {c+d \tan (e+f x)}\right )}{(a+i b)^3 d f}\\ &=-\frac {(A-i B-C) (c-i d)^{3/2} \tanh ^{-1}\left (\frac {\sqrt {c+d \tan (e+f x)}}{\sqrt {c-i d}}\right )}{(i a+b)^3 f}+\frac {(A+i B-C) (c+i d)^{3/2} \tanh ^{-1}\left (\frac {\sqrt {c+d \tan (e+f x)}}{\sqrt {c+i d}}\right )}{(i a-b)^3 f}-\frac {\left (a^5 b B d^2+3 a^6 C d^2+a^4 b^2 d (4 B c+3 (A+2 C) d)-b^6 \left (8 A c^2-8 c^2 C-12 B c d-3 A d^2\right )+a^2 b^4 \left (24 A c^2-24 c^2 C-48 B c d-26 A d^2+35 C d^2\right )-2 a^3 b^3 \left (12 c (A-C) d+B \left (4 c^2-9 d^2\right )\right )+a b^5 \left (40 c (A-C) d+3 B \left (8 c^2-5 d^2\right )\right )\right ) \tanh ^{-1}\left (\frac {\sqrt {b} \sqrt {c+d \tan (e+f x)}}{\sqrt {b c-a d}}\right )}{4 b^{5/2} \left (a^2+b^2\right )^3 \sqrt {b c-a d} f}-\frac {\left (a^3 b B d+3 a^4 C d+b^4 (4 B c+3 A d)+a b^3 (8 A c-8 c C-7 B d)-a^2 b^2 (4 B c+5 A d-11 C d)\right ) \sqrt {c+d \tan (e+f x)}}{4 b^2 \left (a^2+b^2\right )^2 f (a+b \tan (e+f x))}-\frac {\left (A b^2-a (b B-a C)\right ) (c+d \tan (e+f x))^{3/2}}{2 b \left (a^2+b^2\right ) f (a+b \tan (e+f x))^2}\\ \end {align*}
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Mathematica [B] time = 6.56, size = 7678, normalized size = 14.43 \[ \text {Result too large to show} \]
Antiderivative was successfully verified.
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fricas [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [B] time = 0.83, size = 14441, normalized size = 27.14 \[ \text {output too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F(-2)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: ValueError} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F(-1)] time = 0.00, size = -1, normalized size = -0.00 \[ \text {Hanged} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\left (c + d \tan {\left (e + f x \right )}\right )^{\frac {3}{2}} \left (A + B \tan {\left (e + f x \right )} + C \tan ^{2}{\left (e + f x \right )}\right )}{\left (a + b \tan {\left (e + f x \right )}\right )^{3}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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